Base | Representation |
---|---|
bin | 1100000001000001100111… |
… | …01110001010011100000101 |
3 | 10110120001200121021121101221 |
4 | 12000200303232022130011 |
5 | 11430410320133410024 |
6 | 132110442532120341 |
7 | 5365015060535353 |
oct | 600406356123405 |
9 | 113501617247357 |
10 | 26423506544389 |
11 | 8468167648579 |
12 | 2b69076a660b1 |
13 | 1198958c77b16 |
14 | 674c940b87d3 |
15 | 30c5092343e4 |
hex | 180833b8a705 |
26423506544389 has 2 divisors, whose sum is σ = 26423506544390. Its totient is φ = 26423506544388.
The previous prime is 26423506544339. The next prime is 26423506544417. The reversal of 26423506544389 is 98344560532462.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14904155148100 + 11519351396289 = 3860590^2 + 3394017^2 .
It is a cyclic number.
It is not a de Polignac number, because 26423506544389 - 215 = 26423506511621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (26423506544339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13211753272194 + 13211753272195.
It is an arithmetic number, because the mean of its divisors is an integer number (13211753272195).
Almost surely, 226423506544389 is an apocalyptic number.
It is an amenable number.
26423506544389 is a deficient number, since it is larger than the sum of its proper divisors (1).
26423506544389 is an equidigital number, since it uses as much as digits as its factorization.
26423506544389 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 149299200, while the sum is 61.
The spelling of 26423506544389 in words is "twenty-six trillion, four hundred twenty-three billion, five hundred six million, five hundred forty-four thousand, three hundred eighty-nine".
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