Base | Representation |
---|---|
bin | 11000100111100110… |
… | …001001010111100001 |
3 | 2112020020110011210211 |
4 | 120213212021113201 |
5 | 413114113140131 |
6 | 20051010454121 |
7 | 1624030161535 |
oct | 304746112741 |
9 | 75206404724 |
10 | 26434115041 |
11 | 10235406974 |
12 | 5158894341 |
13 | 265369acb9 |
14 | 13caa19bc5 |
15 | a4aa555b1 |
hex | 6279895e1 |
26434115041 has 2 divisors, whose sum is σ = 26434115042. Its totient is φ = 26434115040.
The previous prime is 26434114969. The next prime is 26434115063. The reversal of 26434115041 is 14051143462.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16948134225 + 9485980816 = 130185^2 + 97396^2 .
It is a cyclic number.
It is not a de Polignac number, because 26434115041 - 27 = 26434114913 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 26434114994 and 26434115012.
It is not a weakly prime, because it can be changed into another prime (26434110041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13217057520 + 13217057521.
It is an arithmetic number, because the mean of its divisors is an integer number (13217057521).
Almost surely, 226434115041 is an apocalyptic number.
It is an amenable number.
26434115041 is a deficient number, since it is larger than the sum of its proper divisors (1).
26434115041 is an equidigital number, since it uses as much as digits as its factorization.
26434115041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
The spelling of 26434115041 in words is "twenty-six billion, four hundred thirty-four million, one hundred fifteen thousand, forty-one".
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