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264401103504053 is a prime number
BaseRepresentation
bin111100000111100010101101…
…110110100100001010110101
31021200011111110111201110110002
4330013202231312210022311
5234123421424444112203
62334200105022041045
7106456230553066355
oct7407425566441265
91250144414643402
10264401103504053
117727897300733a
12257a2856719185
13b46bbbca809b9
144941120230b65
152087a2d31ed88
hexf078adda42b5

264401103504053 has 2 divisors, whose sum is σ = 264401103504054. Its totient is φ = 264401103504052.

The previous prime is 264401103503993. The next prime is 264401103504071. The reversal of 264401103504053 is 350405301104462.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 242978480046289 + 21422623457764 = 15587767^2 + 4628458^2 .

It is a cyclic number.

It is not a de Polignac number, because 264401103504053 - 218 = 264401103241909 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 264401103503998 and 264401103504016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (264401103504253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132200551752026 + 132200551752027.

It is an arithmetic number, because the mean of its divisors is an integer number (132200551752027).

Almost surely, 2264401103504053 is an apocalyptic number.

It is an amenable number.

264401103504053 is a deficient number, since it is larger than the sum of its proper divisors (1).

264401103504053 is an equidigital number, since it uses as much as digits as its factorization.

264401103504053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 38.

The spelling of 264401103504053 in words is "two hundred sixty-four trillion, four hundred one billion, one hundred three million, five hundred four thousand, fifty-three".