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2644365053557 is a prime number
BaseRepresentation
bin100110011110110000011…
…100001000111001110101
3100100210120100101010202001
4212132300130020321311
5321311124423203212
65342445440215301
7362022555042403
oct46366034107165
910323510333661
102644365053557
1192a5181527a7
123685b460a531
131624936bc856
1491db8d20473
1548bbcb66657
hex267b0708e75

2644365053557 has 2 divisors, whose sum is σ = 2644365053558. Its totient is φ = 2644365053556.

The previous prime is 2644365053507. The next prime is 2644365053581. The reversal of 2644365053557 is 7553505634462.

2644365053557 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2458495425681 + 185869627876 = 1567959^2 + 431126^2 .

It is a cyclic number.

It is not a de Polignac number, because 2644365053557 - 235 = 2610005315189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2644365053498 and 2644365053507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2644365053507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1322182526778 + 1322182526779.

It is an arithmetic number, because the mean of its divisors is an integer number (1322182526779).

Almost surely, 22644365053557 is an apocalyptic number.

It is an amenable number.

2644365053557 is a deficient number, since it is larger than the sum of its proper divisors (1).

2644365053557 is an equidigital number, since it uses as much as digits as its factorization.

2644365053557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45360000, while the sum is 55.

The spelling of 2644365053557 in words is "two trillion, six hundred forty-four billion, three hundred sixty-five million, fifty-three thousand, five hundred fifty-seven".