Base | Representation |
---|---|
bin | 11111100011100… |
… | …10011110011001 |
3 | 200110002122220121 |
4 | 33301302132121 |
5 | 1020231210131 |
6 | 42133353241 |
7 | 6362666251 |
oct | 1761623631 |
9 | 613078817 |
10 | 264710041 |
11 | 126470632 |
12 | 74798821 |
13 | 42ac307b |
14 | 27228961 |
15 | 1838c911 |
hex | fc72799 |
264710041 has 2 divisors, whose sum is σ = 264710042. Its totient is φ = 264710040.
The previous prime is 264710029. The next prime is 264710051. The reversal of 264710041 is 140017462.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 183331600 + 81378441 = 13540^2 + 9021^2 .
It is a cyclic number.
It is not a de Polignac number, because 264710041 - 217 = 264578969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 264709988 and 264710015.
It is not a weakly prime, because it can be changed into another prime (264710051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132355020 + 132355021.
It is an arithmetic number, because the mean of its divisors is an integer number (132355021).
Almost surely, 2264710041 is an apocalyptic number.
It is an amenable number.
264710041 is a deficient number, since it is larger than the sum of its proper divisors (1).
264710041 is an equidigital number, since it uses as much as digits as its factorization.
264710041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
The square root of 264710041 is about 16269.9121386687. The cubic root of 264710041 is about 642.0814725975.
The spelling of 264710041 in words is "two hundred sixty-four million, seven hundred ten thousand, forty-one".
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