Base | Representation |
---|---|
bin | 11111100101001… |
… | …01000000101001 |
3 | 200110111011211222 |
4 | 33302211000221 |
5 | 1020304321113 |
6 | 42142031425 |
7 | 6364520603 |
oct | 1762450051 |
9 | 613434758 |
10 | 264917033 |
11 | 1265a20a7 |
12 | 74878575 |
13 | 42b66354 |
14 | 27280173 |
15 | 183cde08 |
hex | fca5029 |
264917033 has 2 divisors, whose sum is σ = 264917034. Its totient is φ = 264917032.
The previous prime is 264917027. The next prime is 264917053. The reversal of 264917033 is 330719462.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 230189584 + 34727449 = 15172^2 + 5893^2 .
It is a cyclic number.
It is not a de Polignac number, because 264917033 - 24 = 264917017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 264916984 and 264917002.
It is not a weakly prime, because it can be changed into another prime (264917053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132458516 + 132458517.
It is an arithmetic number, because the mean of its divisors is an integer number (132458517).
Almost surely, 2264917033 is an apocalyptic number.
It is an amenable number.
264917033 is a deficient number, since it is larger than the sum of its proper divisors (1).
264917033 is an equidigital number, since it uses as much as digits as its factorization.
264917033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27216, while the sum is 35.
The square root of 264917033 is about 16276.2720854623. The cubic root of 264917033 is about 642.2487891332.
The spelling of 264917033 in words is "two hundred sixty-four million, nine hundred seventeen thousand, thirty-three".
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