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2649713306437 is a prime number
BaseRepresentation
bin100110100011101111001…
…110000110101101000101
3100101022101002001112110001
4212203233032012231011
5321403103101301222
65345132252001301
7362302236326401
oct46435716065505
910338332045401
102649713306437
119318120a12aa
12369647760231
13162b36742322
1492365356101
1548dd245de27
hex268ef386b45

2649713306437 has 2 divisors, whose sum is σ = 2649713306438. Its totient is φ = 2649713306436.

The previous prime is 2649713306389. The next prime is 2649713306453. The reversal of 2649713306437 is 7346033179462.

It is a Cunningham number, because it is equal to 16277942+1.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2649713306436 + 1 = 1627794^2 + 1^2 .

It is a cyclic number.

It is not a de Polignac number, because 2649713306437 - 27 = 2649713306309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2649713304437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1324856653218 + 1324856653219.

It is an arithmetic number, because the mean of its divisors is an integer number (1324856653219).

Almost surely, 22649713306437 is an apocalyptic number.

It is an amenable number.

2649713306437 is a deficient number, since it is larger than the sum of its proper divisors (1).

2649713306437 is an equidigital number, since it uses as much as digits as its factorization.

2649713306437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13716864, while the sum is 55.

The spelling of 2649713306437 in words is "two trillion, six hundred forty-nine billion, seven hundred thirteen million, three hundred six thousand, four hundred thirty-seven".