Base | Representation |
---|---|
bin | 1001110111110101… |
… | …1110110110001001 |
3 | 20211200201001200212 |
4 | 2131331132312021 |
5 | 20411413440131 |
6 | 1114545410505 |
7 | 122446550543 |
oct | 23575366611 |
9 | 6750631625 |
10 | 2650140041 |
11 | 113aa3148a |
12 | 61b639a35 |
13 | 33307a003 |
14 | 1b1d74693 |
15 | 1079d6a2b |
hex | 9df5ed89 |
2650140041 has 2 divisors, whose sum is σ = 2650140042. Its totient is φ = 2650140040.
The previous prime is 2650140023. The next prime is 2650140049. The reversal of 2650140041 is 1400410562.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2270046025 + 380094016 = 47645^2 + 19496^2 .
It is a cyclic number.
It is not a de Polignac number, because 2650140041 - 214 = 2650123657 is a prime.
It is a super-2 number, since 2×26501400412 = 14046484473822963362, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2650139989 and 2650140016.
It is not a weakly prime, because it can be changed into another prime (2650140049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1325070020 + 1325070021.
It is an arithmetic number, because the mean of its divisors is an integer number (1325070021).
Almost surely, 22650140041 is an apocalyptic number.
It is an amenable number.
2650140041 is a deficient number, since it is larger than the sum of its proper divisors (1).
2650140041 is an equidigital number, since it uses as much as digits as its factorization.
2650140041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 23.
The square root of 2650140041 is about 51479.5108853998. The cubic root of 2650140041 is about 1383.8518796412.
The spelling of 2650140041 in words is "two billion, six hundred fifty million, one hundred forty thousand, forty-one".
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