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2651210053241 is a prime number
BaseRepresentation
bin100110100101001000011…
…011101111011001111001
3100101110020101110011001212
4212211020123233121321
5321414134233200431
65345541000252505
7362354312424611
oct46451033573171
910343211404055
102651210053241
1193240aa5a332
123699a4a71135
13163014865919
149246804da41
1548e6da6472b
hex269486ef679

2651210053241 has 2 divisors, whose sum is σ = 2651210053242. Its totient is φ = 2651210053240.

The previous prime is 2651210053223. The next prime is 2651210053249. The reversal of 2651210053241 is 1423500121562.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2643862992016 + 7347061225 = 1625996^2 + 85715^2 .

It is a cyclic number.

It is not a de Polignac number, because 2651210053241 - 210 = 2651210052217 is a prime.

It is a super-2 number, since 2×26512100532412 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2651210053198 and 2651210053207.

It is not a weakly prime, because it can be changed into another prime (2651210053249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1325605026620 + 1325605026621.

It is an arithmetic number, because the mean of its divisors is an integer number (1325605026621).

Almost surely, 22651210053241 is an apocalyptic number.

It is an amenable number.

2651210053241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2651210053241 is an equidigital number, since it uses as much as digits as its factorization.

2651210053241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

The spelling of 2651210053241 in words is "two trillion, six hundred fifty-one billion, two hundred ten million, fifty-three thousand, two hundred forty-one".