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26517311007613 is a prime number
BaseRepresentation
bin1100000011110000010101…
…11001110010101101111101
310110220000210222221001221121
412001320022321302231331
511433424423104220423
6132221515015230541
75404545454400416
oct601701271625575
9113800728831847
1026517311007613
1184a3a23839148
122b83295978451
1311a4758037b6a
1467963238a80d
1530eb995ae45d
hex181e0ae72b7d

26517311007613 has 2 divisors, whose sum is σ = 26517311007614. Its totient is φ = 26517311007612.

The previous prime is 26517311007601. The next prime is 26517311007631. The reversal of 26517311007613 is 31670011371562.

Together with next prime (26517311007631) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 23191130224089 + 3326180783524 = 4815717^2 + 1823782^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-26517311007613 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 26517311007613.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (26517311007013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13258655503806 + 13258655503807.

It is an arithmetic number, because the mean of its divisors is an integer number (13258655503807).

Almost surely, 226517311007613 is an apocalyptic number.

It is an amenable number.

26517311007613 is a deficient number, since it is larger than the sum of its proper divisors (1).

26517311007613 is an equidigital number, since it uses as much as digits as its factorization.

26517311007613 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 158760, while the sum is 43.

The spelling of 26517311007613 in words is "twenty-six trillion, five hundred seventeen billion, three hundred eleven million, seven thousand, six hundred thirteen".