Base | Representation |
---|---|
bin | 111100010011001110100110… |
… | …101011100010000000000111 |
3 | 1021210000021020122102121022122 |
4 | 330103032212223202000013 |
5 | 234230101040331233211 |
6 | 2340013033445120155 |
7 | 106601236604126645 |
oct | 7423164653420007 |
9 | 1253007218377278 |
10 | 265204142055431 |
11 | 77558499372717 |
12 | 258b240a6b905b |
13 | b4c98493bbc67 |
14 | 496bd3dd56195 |
15 | 209d87d26d6db |
hex | f133a6ae2007 |
265204142055431 has 2 divisors, whose sum is σ = 265204142055432. Its totient is φ = 265204142055430.
The previous prime is 265204142055371. The next prime is 265204142055451. The reversal of 265204142055431 is 134550241402562.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 265204142055431 - 218 = 265204141793287 is a prime.
It is a super-3 number, since 3×2652041420554313 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (265204142055451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132602071027715 + 132602071027716.
It is an arithmetic number, because the mean of its divisors is an integer number (132602071027716).
Almost surely, 2265204142055431 is an apocalyptic number.
265204142055431 is a deficient number, since it is larger than the sum of its proper divisors (1).
265204142055431 is an equidigital number, since it uses as much as digits as its factorization.
265204142055431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152000, while the sum is 44.
Adding to 265204142055431 its reverse (134550241402562), we get a palindrome (399754383457993).
The spelling of 265204142055431 in words is "two hundred sixty-five trillion, two hundred four billion, one hundred forty-two million, fifty-five thousand, four hundred thirty-one".
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