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2652055443131 = 23115306758397
BaseRepresentation
bin100110100101111010110…
…100101001011010111011
3100101112102022012101222112
4212211322310221122323
5321422402143140011
65350200520042535
7362414256215303
oct46457264513273
910345368171875
102652055443131
11932804182266
12369ba000344b
1316311aa4b723
1492508432603
1548ebcda558b
hex2697ad296bb

2652055443131 has 4 divisors (see below), whose sum is σ = 2767362201552. Its totient is φ = 2536748684712.

The previous prime is 2652055443067. The next prime is 2652055443157. The reversal of 2652055443131 is 1313445502562.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2652055443131 - 26 = 2652055443067 is a prime.

It is a super-2 number, since 2×26520554431312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2652055443161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57653379176 + ... + 57653379221.

It is an arithmetic number, because the mean of its divisors is an integer number (691840550388).

Almost surely, 22652055443131 is an apocalyptic number.

2652055443131 is a deficient number, since it is larger than the sum of its proper divisors (115306758421).

2652055443131 is a wasteful number, since it uses less digits than its factorization.

2652055443131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115306758420.

The product of its (nonzero) digits is 432000, while the sum is 41.

The spelling of 2652055443131 in words is "two trillion, six hundred fifty-two billion, fifty-five million, four hundred forty-three thousand, one hundred thirty-one".

Divisors: 1 23 115306758397 2652055443131