Base | Representation |
---|---|
bin | 11000101101100011… |
… | …101001111010011101 |
3 | 2112111012122012222021 |
4 | 120231203221322131 |
5 | 413320214001323 |
6 | 20104542220141 |
7 | 1626353225431 |
oct | 305543517235 |
9 | 75435565867 |
10 | 26534125213 |
11 | 10286905002 |
12 | 5186284651 |
13 | 266b31630b |
14 | 13da0109c1 |
15 | a5470d05d |
hex | 62d8e9e9d |
26534125213 has 4 divisors (see below), whose sum is σ = 27390064768. Its totient is φ = 25678185660.
The previous prime is 26534125201. The next prime is 26534125223. The reversal of 26534125213 is 31252143562.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 26534125213 - 217 = 26533994141 is a prime.
It is a super-4 number, since 4×265341252134 (a number of 43 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (26534125223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 427969731 + ... + 427969792.
It is an arithmetic number, because the mean of its divisors is an integer number (6847516192).
Almost surely, 226534125213 is an apocalyptic number.
It is an amenable number.
26534125213 is a deficient number, since it is larger than the sum of its proper divisors (855939555).
26534125213 is an equidigital number, since it uses as much as digits as its factorization.
26534125213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 855939554.
The product of its digits is 43200, while the sum is 34.
Adding to 26534125213 its reverse (31252143562), we get a palindrome (57786268775).
The spelling of 26534125213 in words is "twenty-six billion, five hundred thirty-four million, one hundred twenty-five thousand, two hundred thirteen".
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