Base | Representation |
---|---|
bin | 1100000100011110010110… |
… | …01010001011001100110111 |
3 | 10110222101120102000012012112 |
4 | 12002033023022023030313 |
5 | 11434331014402123101 |
6 | 132241122013441235 |
7 | 5406411533065613 |
oct | 602171312131467 |
9 | 113871512005175 |
10 | 26542011364151 |
11 | 8503449514648 |
12 | 2b88029aa021b |
13 | 11a6b9346994a |
14 | 67a8d6a14343 |
15 | 310642ce36bb |
hex | 1823cb28b337 |
26542011364151 has 4 divisors (see below), whose sum is σ = 26555756581704. Its totient is φ = 26528266146600.
The previous prime is 26542011364147. The next prime is 26542011364177. The reversal of 26542011364151 is 15146311024562.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 26542011364151 - 22 = 26542011364147 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 26542011364099 and 26542011364108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (26542011364181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6872605880 + ... + 6872609741.
It is an arithmetic number, because the mean of its divisors is an integer number (6638939145426).
Almost surely, 226542011364151 is an apocalyptic number.
26542011364151 is a deficient number, since it is larger than the sum of its proper divisors (13745217553).
26542011364151 is a wasteful number, since it uses less digits than its factorization.
26542011364151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13745217552.
The product of its (nonzero) digits is 172800, while the sum is 41.
The spelling of 26542011364151 in words is "twenty-six trillion, five hundred forty-two billion, eleven million, three hundred sixty-four thousand, one hundred fifty-one".
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