Base | Representation |
---|---|
bin | 11000101110000001… |
… | …110100110011010011 |
3 | 2112111202112000222011 |
4 | 120232001310303103 |
5 | 413324230043011 |
6 | 20105423523351 |
7 | 1626510365464 |
oct | 305601646323 |
9 | 75452460864 |
10 | 26542034131 |
11 | 102903170a8 |
12 | 5188a59557 |
13 | 266cb55152 |
14 | 13db0acd6b |
15 | a55271621 |
hex | 62e074cd3 |
26542034131 has 2 divisors, whose sum is σ = 26542034132. Its totient is φ = 26542034130.
The previous prime is 26542034089. The next prime is 26542034137. The reversal of 26542034131 is 13143024562.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26542034131 - 29 = 26542033619 is a prime.
It is a super-2 number, since 2×265420341312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 26542034093 and 26542034102.
It is not a weakly prime, because it can be changed into another prime (26542034137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13271017065 + 13271017066.
It is an arithmetic number, because the mean of its divisors is an integer number (13271017066).
Almost surely, 226542034131 is an apocalyptic number.
26542034131 is a deficient number, since it is larger than the sum of its proper divisors (1).
26542034131 is an equidigital number, since it uses as much as digits as its factorization.
26542034131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 26542034131 its reverse (13143024562), we get a palindrome (39685058693).
The spelling of 26542034131 in words is "twenty-six billion, five hundred forty-two million, thirty-four thousand, one hundred thirty-one".
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