Base | Representation |
---|---|
bin | 1001111001000001… |
… | …1111011010011111 |
3 | 20212001002020011201 |
4 | 2132100133122133 |
5 | 20414202414403 |
6 | 1115244300331 |
7 | 122540113453 |
oct | 23620373237 |
9 | 6761066151 |
10 | 2655123103 |
11 | 1142825316 |
12 | 6212416a7 |
13 | 334103179 |
14 | 1b28b0663 |
15 | 10816d21d |
hex | 9e41f69f |
2655123103 has 4 divisors (see below), whose sum is σ = 2655244120. Its totient is φ = 2655002088.
The previous prime is 2655123083. The next prime is 2655123113. The reversal of 2655123103 is 3013215562.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 2655123103 - 213 = 2655114911 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2655123113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17325 + ... + 74902.
It is an arithmetic number, because the mean of its divisors is an integer number (663811030).
Almost surely, 22655123103 is an apocalyptic number.
2655123103 is a deficient number, since it is larger than the sum of its proper divisors (121017).
2655123103 is an equidigital number, since it uses as much as digits as its factorization.
2655123103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 121016.
The product of its (nonzero) digits is 5400, while the sum is 28.
The square root of 2655123103 is about 51527.8866537334. The cubic root of 2655123103 is about 1384.7186894505.
Adding to 2655123103 its reverse (3013215562), we get a palindrome (5668338665).
The spelling of 2655123103 in words is "two billion, six hundred fifty-five million, one hundred twenty-three thousand, one hundred three".
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