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26568000433 = 132741745601
BaseRepresentation
bin11000101111100100…
…111000001110110001
32112120120101021001001
4120233210320032301
5413402402003213
620112152242001
71630244164132
oct305744701661
975516337031
1026568000433
11102a3a41a57
1251956a0301
132675347120
14140070bc89
15a576a01dd
hex62f9383b1

26568000433 has 8 divisors (see below), whose sum is σ = 28622169576. Its totient is φ = 24515328000.

The previous prime is 26568000421. The next prime is 26568000457. The reversal of 26568000433 is 33400086562.

It can be written as a sum of positive squares in 4 ways, for example, as 2098281249 + 24469719184 = 45807^2 + 156428^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 26568000433 - 233 = 17978065841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 26568000392 and 26568000401.

It is not an unprimeable number, because it can be changed into a prime (26568000413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 337168 + ... + 408433.

It is an arithmetic number, because the mean of its divisors is an integer number (3577771197).

Almost surely, 226568000433 is an apocalyptic number.

It is an amenable number.

26568000433 is a deficient number, since it is larger than the sum of its proper divisors (2054169143).

26568000433 is a wasteful number, since it uses less digits than its factorization.

26568000433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 748355.

The product of its (nonzero) digits is 103680, while the sum is 37.

Adding to 26568000433 its reverse (33400086562), we get a palindrome (59968086995).

The spelling of 26568000433 in words is "twenty-six billion, five hundred sixty-eight million, four hundred thirty-three", and thus it is an aban number.

Divisors: 1 13 2741 35633 745601 9692813 2043692341 26568000433