Base | Representation |
---|---|
bin | 1100001000100010001001… |
… | …11110110010111011011011 |
3 | 10111110201121012111010100011 |
4 | 12010101010332302323123 |
5 | 11444122200000424341 |
6 | 132425150442022351 |
7 | 5422450204204465 |
oct | 604210476627333 |
9 | 114421535433304 |
10 | 26681494154971 |
11 | 8557615957887 |
12 | 2bab0764a79b7 |
13 | 11b7091b2c7b6 |
14 | 68356968b135 |
15 | 3140a83ecb81 |
hex | 184444fb2edb |
26681494154971 has 2 divisors, whose sum is σ = 26681494154972. Its totient is φ = 26681494154970.
The previous prime is 26681494154759. The next prime is 26681494155011. The reversal of 26681494154971 is 17945149418662.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26681494154971 - 225 = 26681460600539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 26681494154897 and 26681494154906.
It is not a weakly prime, because it can be changed into another prime (26681492154971) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13340747077485 + 13340747077486.
It is an arithmetic number, because the mean of its divisors is an integer number (13340747077486).
Almost surely, 226681494154971 is an apocalyptic number.
26681494154971 is a deficient number, since it is larger than the sum of its proper divisors (1).
26681494154971 is an equidigital number, since it uses as much as digits as its factorization.
26681494154971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 104509440, while the sum is 67.
The spelling of 26681494154971 in words is "twenty-six trillion, six hundred eighty-one billion, four hundred ninety-four million, one hundred fifty-four thousand, nine hundred seventy-one".
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