Base | Representation |
---|---|
bin | 100110110101000100100… |
… | …101011000001110001111 |
3 | 100110002102011212210202012 |
4 | 212311010211120032033 |
5 | 322204212241340142 |
6 | 5401451200251435 |
7 | 363531406110143 |
oct | 46650445301617 |
9 | 10402364783665 |
10 | 2668325340047 |
11 | 9396a3100664 |
12 | 371180910b7b |
13 | 1648116c2873 |
14 | 9320d17d223 |
15 | 49621410882 |
hex | 26d4495838f |
2668325340047 has 4 divisors (see below), whose sum is σ = 2668664268960. Its totient is φ = 2667986411136.
The previous prime is 2668325340001. The next prime is 2668325340139. The reversal of 2668325340047 is 7400435238662.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2668325340047 - 220 = 2668324291471 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2668325339977 and 2668325340004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2668325345047) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169452647 + ... + 169468392.
It is an arithmetic number, because the mean of its divisors is an integer number (667166067240).
Almost surely, 22668325340047 is an apocalyptic number.
2668325340047 is a deficient number, since it is larger than the sum of its proper divisors (338928913).
2668325340047 is an equidigital number, since it uses as much as digits as its factorization.
2668325340047 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 338928912.
The product of its (nonzero) digits is 5806080, while the sum is 50.
The spelling of 2668325340047 in words is "two trillion, six hundred sixty-eight billion, three hundred twenty-five million, three hundred forty thousand, forty-seven".
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