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2668325340047 = 7873338921039
BaseRepresentation
bin100110110101000100100…
…101011000001110001111
3100110002102011212210202012
4212311010211120032033
5322204212241340142
65401451200251435
7363531406110143
oct46650445301617
910402364783665
102668325340047
119396a3100664
12371180910b7b
131648116c2873
149320d17d223
1549621410882
hex26d4495838f

2668325340047 has 4 divisors (see below), whose sum is σ = 2668664268960. Its totient is φ = 2667986411136.

The previous prime is 2668325340001. The next prime is 2668325340139. The reversal of 2668325340047 is 7400435238662.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2668325340047 - 220 = 2668324291471 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2668325339977 and 2668325340004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2668325345047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169452647 + ... + 169468392.

It is an arithmetic number, because the mean of its divisors is an integer number (667166067240).

Almost surely, 22668325340047 is an apocalyptic number.

2668325340047 is a deficient number, since it is larger than the sum of its proper divisors (338928913).

2668325340047 is an equidigital number, since it uses as much as digits as its factorization.

2668325340047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 338928912.

The product of its (nonzero) digits is 5806080, while the sum is 50.

The spelling of 2668325340047 in words is "two trillion, six hundred sixty-eight billion, three hundred twenty-five million, three hundred forty thousand, forty-seven".

Divisors: 1 7873 338921039 2668325340047