Base | Representation |
---|---|
bin | 1111100010011011111… |
… | …1110111000011011101 |
3 | 221112000122221011222211 |
4 | 3320212333313003131 |
5 | 13333144203402013 |
6 | 322344230440421 |
7 | 25200035443162 |
oct | 3704677670335 |
9 | 845018834884 |
10 | 266942247133 |
11 | a3233a37291 |
12 | 4389a503111 |
13 | 1c2321110b3 |
14 | ccc497a069 |
15 | 6e253d423d |
hex | 3e26ff70dd |
266942247133 has 2 divisors, whose sum is σ = 266942247134. Its totient is φ = 266942247132.
The previous prime is 266942247067. The next prime is 266942247149. The reversal of 266942247133 is 331742249662.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 221988918649 + 44953328484 = 471157^2 + 212022^2 .
It is a cyclic number.
It is not a de Polignac number, because 266942247133 - 229 = 266405376221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (266942247163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 133471123566 + 133471123567.
It is an arithmetic number, because the mean of its divisors is an integer number (133471123567).
Almost surely, 2266942247133 is an apocalyptic number.
It is an amenable number.
266942247133 is a deficient number, since it is larger than the sum of its proper divisors (1).
266942247133 is an equidigital number, since it uses as much as digits as its factorization.
266942247133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2612736, while the sum is 49.
The spelling of 266942247133 in words is "two hundred sixty-six billion, nine hundred forty-two million, two hundred forty-seven thousand, one hundred thirty-three".
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