Base | Representation |
---|---|
bin | 1111101000010110001… |
… | …1101101101110010011 |
3 | 221200010020010120020111 |
4 | 3322011203231232103 |
5 | 13344421322020103 |
6 | 323205502022151 |
7 | 25254251220061 |
oct | 3720543555623 |
9 | 850106116214 |
10 | 268528704403 |
11 | a39784a90a3 |
12 | 44061877957 |
13 | 1c4259b48cb |
14 | cdd5547031 |
15 | 6eb980a86d |
hex | 3e858edb93 |
268528704403 has 4 divisors (see below), whose sum is σ = 280203865488. Its totient is φ = 256853543320.
The previous prime is 268528704373. The next prime is 268528704421. The reversal of 268528704403 is 304407825862.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 268528704403 - 217 = 268528573331 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (268528704203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5837580508 + ... + 5837580553.
It is an arithmetic number, because the mean of its divisors is an integer number (70050966372).
Almost surely, 2268528704403 is an apocalyptic number.
268528704403 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
268528704403 is a deficient number, since it is larger than the sum of its proper divisors (11675161085).
268528704403 is a wasteful number, since it uses less digits than its factorization.
268528704403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11675161084.
The product of its (nonzero) digits is 2580480, while the sum is 49.
The spelling of 268528704403 in words is "two hundred sixty-eight billion, five hundred twenty-eight million, seven hundred four thousand, four hundred three".
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