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2697217054381 is a prime number
BaseRepresentation
bin100111001111111110101…
…010100001011010101101
3100112211222200201222000001
4213033332222201122231
5323142400031220011
65423030122104301
7365603360453353
oct47177652413255
910484880658001
102697217054381
1194a979790223
123768a464b091
13167467295815
149479032d7d3
154a262ab87c1
hex273feaa16ad

2697217054381 has 2 divisors, whose sum is σ = 2697217054382. Its totient is φ = 2697217054380.

The previous prime is 2697217054373. The next prime is 2697217054459. The reversal of 2697217054381 is 1834507127962.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2317902721156 + 379314333225 = 1522466^2 + 615885^2 .

It is a cyclic number.

It is not a de Polignac number, because 2697217054381 - 23 = 2697217054373 is a prime.

It is a super-2 number, since 2×26972170543812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2697217054321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1348608527190 + 1348608527191.

It is an arithmetic number, because the mean of its divisors is an integer number (1348608527191).

It is a 2-persistent number, because it is pandigital, and so is 2⋅2697217054381 = 5394434108762, but 3⋅2697217054381 = 8091651163143 is not.

Almost surely, 22697217054381 is an apocalyptic number.

It is an amenable number.

2697217054381 is a deficient number, since it is larger than the sum of its proper divisors (1).

2697217054381 is an equidigital number, since it uses as much as digits as its factorization.

2697217054381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5080320, while the sum is 55.

The spelling of 2697217054381 in words is "two trillion, six hundred ninety-seven billion, two hundred seventeen million, fifty-four thousand, three hundred eighty-one".