Base | Representation |
---|---|
bin | 110011011111… |
… | …1100010100001 |
3 | 1212210200120221 |
4 | 1212333202201 |
5 | 23402431240 |
6 | 2402403041 |
7 | 445326061 |
oct | 146774241 |
9 | 55720527 |
10 | 26998945 |
11 | 14270786 |
12 | 9060481 |
13 | 579400c |
14 | 382b3a1 |
15 | 2584a4a |
hex | 19bf8a1 |
26998945 has 4 divisors (see below), whose sum is σ = 32398740. Its totient is φ = 21599152.
The previous prime is 26998903. The next prime is 26998967. The reversal of 26998945 is 54989962.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54989962 = 2 ⋅27494981.
It can be written as a sum of positive squares in 2 ways, for example, as 9834496 + 17164449 = 3136^2 + 4143^2 .
It is a cyclic number.
It is not a de Polignac number, because 26998945 - 27 = 26998817 is a prime.
It is a super-2 number, since 2×269989452 = 1457886062226050, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 26998892 and 26998901.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2699890 + ... + 2699899.
It is an arithmetic number, because the mean of its divisors is an integer number (8099685).
Almost surely, 226998945 is an apocalyptic number.
It is an amenable number.
26998945 is a deficient number, since it is larger than the sum of its proper divisors (5399795).
26998945 is an equidigital number, since it uses as much as digits as its factorization.
26998945 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5399794.
The product of its digits is 1399680, while the sum is 52.
The square root of 26998945 is about 5196.0509042926. The cubic root of 26998945 is about 299.9960925417.
The spelling of 26998945 in words is "twenty-six million, nine hundred ninety-eight thousand, nine hundred forty-five".
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