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2750300000057 = 8333136144579
BaseRepresentation
bin101000000001011010101…
…001111000111100111001
3100201221000010200000001002
4220001122221320330321
5330030103300000212
65503245333534345
7402462666164051
oct50013251707471
910657003600032
102750300000057
11970439716a65
12385039aa43b5
1316c47696bb4c
1497188298561
154b81ce38ac2
hex2805aa78f39

2750300000057 has 4 divisors (see below), whose sum is σ = 2783436144720. Its totient is φ = 2717163855396.

The previous prime is 2750300000053. The next prime is 2750300000069. The reversal of 2750300000057 is 7500000030572.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2750300000057 - 22 = 2750300000053 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2750299999975 and 2750300000029.

It is not an unprimeable number, because it can be changed into a prime (2750300000051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16568072207 + ... + 16568072372.

It is an arithmetic number, because the mean of its divisors is an integer number (695859036180).

Almost surely, 22750300000057 is an apocalyptic number.

It is an amenable number.

2750300000057 is a deficient number, since it is larger than the sum of its proper divisors (33136144663).

2750300000057 is an equidigital number, since it uses as much as digits as its factorization.

2750300000057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33136144662.

The product of its (nonzero) digits is 7350, while the sum is 29.

The spelling of 2750300000057 in words is "two trillion, seven hundred fifty billion, three hundred million, fifty-seven", and thus it is an aban number.

Divisors: 1 83 33136144579 2750300000057