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2750300000053 is a prime number
BaseRepresentation
bin101000000001011010101…
…001111000111100110101
3100201221000010200000000221
4220001122221320330311
5330030103300000203
65503245333534341
7402462666164044
oct50013251707465
910657003600027
102750300000053
11970439716a61
12385039aa43b1
1316c47696bb48
149718829855b
154b81ce38abd
hex2805aa78f35

2750300000053 has 2 divisors, whose sum is σ = 2750300000054. Its totient is φ = 2750300000052.

The previous prime is 2750300000051. The next prime is 2750300000069. The reversal of 2750300000053 is 3500000030572.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2419166504689 + 331133495364 = 1555367^2 + 575442^2 .

It is a cyclic number.

It is not a de Polignac number, because 2750300000053 - 21 = 2750300000051 is a prime.

Together with 2750300000051, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2750299999973 and 2750300000027.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2750300000051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1375150000026 + 1375150000027.

It is an arithmetic number, because the mean of its divisors is an integer number (1375150000027).

Almost surely, 22750300000053 is an apocalyptic number.

It is an amenable number.

2750300000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

2750300000053 is an equidigital number, since it uses as much as digits as its factorization.

2750300000053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3150, while the sum is 25.

The spelling of 2750300000053 in words is "two trillion, seven hundred fifty billion, three hundred million, fifty-three", and thus it is an aban number.