Base | Representation |
---|---|
bin | 11010000010001000… |
… | …001111000100100111 |
3 | 2200011002111120021211 |
4 | 122002020033010213 |
5 | 424221432010433 |
6 | 20501425452251 |
7 | 2006462404663 |
oct | 320210170447 |
9 | 80132446254 |
10 | 27953000743 |
11 | 10944816208 |
12 | 55014a1087 |
13 | 2836273435 |
14 | 14d26378a3 |
15 | ad90808cd |
hex | 68220f127 |
27953000743 has 2 divisors, whose sum is σ = 27953000744. Its totient is φ = 27953000742.
The previous prime is 27953000729. The next prime is 27953000749. The reversal of 27953000743 is 34700035972.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 27953000743 - 217 = 27952869671 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 27953000696 and 27953000705.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (27953000749) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13976500371 + 13976500372.
It is an arithmetic number, because the mean of its divisors is an integer number (13976500372).
Almost surely, 227953000743 is an apocalyptic number.
27953000743 is a deficient number, since it is larger than the sum of its proper divisors (1).
27953000743 is an equidigital number, since it uses as much as digits as its factorization.
27953000743 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 158760, while the sum is 40.
The spelling of 27953000743 in words is "twenty-seven billion, nine hundred fifty-three million, seven hundred forty-three", and thus it is an aban number.
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