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28248029113 is a prime number
BaseRepresentation
bin11010010011101101…
…101011011110111001
32200220122122120010111
4122103231223132321
5430322443412423
620551005144321
72020004200003
oct322355533671
980818576114
1028248029113
1110a86304407
12558425b0a1
132882420335
14151d8b5373
15b04e0b60d
hex693b6b7b9

28248029113 has 2 divisors, whose sum is σ = 28248029114. Its totient is φ = 28248029112.

The previous prime is 28248029111. The next prime is 28248029123. The reversal of 28248029113 is 31192084282.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 28127314944 + 120714169 = 167712^2 + 10987^2 .

It is a cyclic number.

It is not a de Polignac number, because 28248029113 - 21 = 28248029111 is a prime.

It is a super-2 number, since 2×282480291132 (a number of 22 digits) contains 22 as substring.

Together with 28248029111, it forms a pair of twin primes.

It is the 168072-nd Hogben number.

It is not a weakly prime, because it can be changed into another prime (28248029111) by changing a digit.

It is a nontrivial repunit in base 168071.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14124014556 + 14124014557.

It is an arithmetic number, because the mean of its divisors is an integer number (14124014557).

Almost surely, 228248029113 is an apocalyptic number.

It is an amenable number.

28248029113 is a deficient number, since it is larger than the sum of its proper divisors (1).

28248029113 is an equidigital number, since it uses as much as digits as its factorization.

28248029113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 40.

The spelling of 28248029113 in words is "twenty-eight billion, two hundred forty-eight million, twenty-nine thousand, one hundred thirteen".