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28313540057 = 112573958187
BaseRepresentation
bin11010010111100111…
…100101010111011001
32201002012220212020202
4122113213211113121
5430441231240212
621001305231545
72021431056005
oct322747452731
981065825222
1028313540057
111100a289790
1255a21925b5
132892b797ca
141528489705
15b0aa4c0c2
hex6979e55d9

28313540057 has 4 divisors (see below), whose sum is σ = 30887498256. Its totient is φ = 25739581860.

The previous prime is 28313540033. The next prime is 28313540071. The reversal of 28313540057 is 75004531382.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 28313540057 - 26 = 28313539993 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 28313540057.

It is not an unprimeable number, because it can be changed into a prime (28313543057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1286979083 + ... + 1286979104.

It is an arithmetic number, because the mean of its divisors is an integer number (7721874564).

Almost surely, 228313540057 is an apocalyptic number.

It is an amenable number.

28313540057 is a deficient number, since it is larger than the sum of its proper divisors (2573958199).

28313540057 is a wasteful number, since it uses less digits than its factorization.

28313540057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2573958198.

The product of its (nonzero) digits is 100800, while the sum is 38.

The spelling of 28313540057 in words is "twenty-eight billion, three hundred thirteen million, five hundred forty thousand, fifty-seven".

Divisors: 1 11 2573958187 28313540057