Base | Representation |
---|---|
bin | 11010011010101000… |
… | …011100101001111101 |
3 | 2201012202001110221120 |
4 | 122122220130221331 |
5 | 431042202120143 |
6 | 21010313021153 |
7 | 2022613566525 |
oct | 323250345175 |
9 | 81182043846 |
10 | 28364098173 |
11 | 11035880854 |
12 | 55b70b47b9 |
13 | 28a049bc58 |
14 | 153108a685 |
15 | b101d7383 |
hex | 69aa1ca7d |
28364098173 has 4 divisors (see below), whose sum is σ = 37818797568. Its totient is φ = 18909398780.
The previous prime is 28364098159. The next prime is 28364098177. The reversal of 28364098173 is 37189046382.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 28364098173 - 25 = 28364098141 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (28364098177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4727349693 + ... + 4727349698.
It is an arithmetic number, because the mean of its divisors is an integer number (9454699392).
Almost surely, 228364098173 is an apocalyptic number.
It is an amenable number.
28364098173 is a deficient number, since it is larger than the sum of its proper divisors (9454699395).
28364098173 is an equidigital number, since it uses as much as digits as its factorization.
28364098173 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9454699394.
The product of its (nonzero) digits is 1741824, while the sum is 51.
The spelling of 28364098173 in words is "twenty-eight billion, three hundred sixty-four million, ninety-eight thousand, one hundred seventy-three".
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