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28889433 = 331069979
BaseRepresentation
bin110111000110…
…1000101011001
32000100201212000
41232031011121
524343430213
62511111213
7500361516
oct156150531
960321760
1028889433
1115342071
129812509
135ca6651
143ba030d
152809c73
hex1b8d159

28889433 has 8 divisors (see below), whose sum is σ = 42799200. Its totient is φ = 19259604.

The previous prime is 28889411. The next prime is 28889453. The reversal of 28889433 is 33498882.

It is not a de Polignac number, because 28889433 - 214 = 28873049 is a prime.

It is a super-3 number, since 3×288894333 (a number of 23 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (28889453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 534963 + ... + 535016.

It is an arithmetic number, because the mean of its divisors is an integer number (5349900).

Almost surely, 228889433 is an apocalyptic number.

It is an amenable number.

28889433 is a deficient number, since it is larger than the sum of its proper divisors (13909767).

28889433 is a wasteful number, since it uses less digits than its factorization.

28889433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1069988 (or 1069982 counting only the distinct ones).

The product of its digits is 331776, while the sum is 45.

The square root of 28889433 is about 5374.8891151353. The cubic root of 28889433 is about 306.8407291354.

It can be divided in two parts, 2888 and 9433, that added together give a palindrome (12321).

The spelling of 28889433 in words is "twenty-eight million, eight hundred eighty-nine thousand, four hundred thirty-three".

Divisors: 1 3 9 27 1069979 3209937 9629811 28889433