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28997221353 = 39665740451
BaseRepresentation
bin11011000000010111…
…100111101111101001
32202211212101110200020
4123000113213233221
5433341242040403
621153211031053
72044402212642
oct330027475751
982755343606
1028997221353
11113301a2651
12575313b489
1329716c4259
1415911b66c9
15b4aa99453
hex6c05e7be9

28997221353 has 4 divisors (see below), whose sum is σ = 38662961808. Its totient is φ = 19331480900.

The previous prime is 28997221327. The next prime is 28997221373. The reversal of 28997221353 is 35312279982.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 28997221353 - 25 = 28997221321 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 28997221296 and 28997221305.

It is not an unprimeable number, because it can be changed into a prime (28997221303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4832870223 + ... + 4832870228.

It is an arithmetic number, because the mean of its divisors is an integer number (9665740452).

Almost surely, 228997221353 is an apocalyptic number.

It is an amenable number.

28997221353 is a deficient number, since it is larger than the sum of its proper divisors (9665740455).

28997221353 is an equidigital number, since it uses as much as digits as its factorization.

28997221353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9665740454.

The product of its digits is 1632960, while the sum is 51.

The spelling of 28997221353 in words is "twenty-eight billion, nine hundred ninety-seven million, two hundred twenty-one thousand, three hundred fifty-three".

Divisors: 1 3 9665740451 28997221353