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29100112113 = 39700037371
BaseRepresentation
bin11011000110100000…
…000111100011110001
32210010000222212021010
4123012200013203301
5434044112041423
621211324221133
72050061605002
oct330640074361
983100885233
1029100112113
1111383288a36
12578169a7a9
132989b0a767
1415a0b1b1a9
15b54b20693
hex6c68078f1

29100112113 has 4 divisors (see below), whose sum is σ = 38800149488. Its totient is φ = 19400074740.

The previous prime is 29100112091. The next prime is 29100112157. The reversal of 29100112113 is 31121100192.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 29100112113 - 224 = 29083334897 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 29100112113.

It is not an unprimeable number, because it can be changed into a prime (29100112513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4850018683 + ... + 4850018688.

It is an arithmetic number, because the mean of its divisors is an integer number (9700037372).

Almost surely, 229100112113 is an apocalyptic number.

It is an amenable number.

29100112113 is a deficient number, since it is larger than the sum of its proper divisors (9700037375).

29100112113 is an equidigital number, since it uses as much as digits as its factorization.

29100112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9700037374.

The product of its (nonzero) digits is 108, while the sum is 21.

The spelling of 29100112113 in words is "twenty-nine billion, one hundred million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 9700037371 29100112113