Base | Representation |
---|---|
bin | 11011001000110110… |
… | …010110011100000111 |
3 | 2210012210002200222002 |
4 | 123020312112130013 |
5 | 434134202312123 |
6 | 21215252255515 |
7 | 2051050421636 |
oct | 331066263407 |
9 | 83183080862 |
10 | 29139494663 |
11 | 113a35376a4 |
12 | 579291159b |
13 | 2995019246 |
14 | 15a604d51d |
15 | b582ee528 |
hex | 6c8d96707 |
29139494663 has 2 divisors, whose sum is σ = 29139494664. Its totient is φ = 29139494662.
The previous prime is 29139494569. The next prime is 29139494693. The reversal of 29139494663 is 36649493192.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 29139494663 - 210 = 29139493639 is a prime.
It is a super-2 number, since 2×291394946632 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 29139494599 and 29139494608.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (29139494693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14569747331 + 14569747332.
It is an arithmetic number, because the mean of its divisors is an integer number (14569747332).
Almost surely, 229139494663 is an apocalyptic number.
29139494663 is a deficient number, since it is larger than the sum of its proper divisors (1).
29139494663 is an equidigital number, since it uses as much as digits as its factorization.
29139494663 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7558272, while the sum is 56.
The spelling of 29139494663 in words is "twenty-nine billion, one hundred thirty-nine million, four hundred ninety-four thousand, six hundred sixty-three".
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