Base | Representation |
---|---|
bin | 11011001101000111… |
… | …100010111100011001 |
3 | 2210101202212012101011 |
4 | 123031013202330121 |
5 | 434311021024233 |
6 | 21230331253521 |
7 | 2052610230325 |
oct | 331507427431 |
9 | 83352765334 |
10 | 29211111193 |
11 | 1142aa02210 |
12 | 57b28aa2a1 |
13 | 29a6b027a4 |
14 | 15b1772985 |
15 | b5e7490cd |
hex | 6cd1e2f19 |
29211111193 has 4 divisors (see below), whose sum is σ = 31866666768. Its totient is φ = 26555555620.
The previous prime is 29211111187. The next prime is 29211111211. The reversal of 29211111193 is 39111111292.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 29211111193 - 225 = 29177556761 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (29211111103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1327777771 + ... + 1327777792.
It is an arithmetic number, because the mean of its divisors is an integer number (7966666692).
Almost surely, 229211111193 is an apocalyptic number.
It is an amenable number.
29211111193 is a deficient number, since it is larger than the sum of its proper divisors (2655555575).
29211111193 is a wasteful number, since it uses less digits than its factorization.
29211111193 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2655555574.
The product of its digits is 972, while the sum is 31.
Subtracting 29211111193 from its reverse (39111111292), we obtain a palindrome (9900000099).
The spelling of 29211111193 in words is "twenty-nine billion, two hundred eleven million, one hundred eleven thousand, one hundred ninety-three".
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