Base | Representation |
---|---|
bin | 101010100100001101110… |
… | …101001011101110000111 |
3 | 101100122012120200120221201 |
4 | 222210031311023232013 |
5 | 340411103310232043 |
6 | 10115435150523331 |
7 | 421221552224425 |
oct | 52441565135607 |
9 | 11318176616851 |
10 | 2925104774023 |
11 | a28591429a03 |
12 | 3b2aa3806547 |
13 | 182ab417c443 |
14 | a180c0d4115 |
15 | 5114e4c5c4d |
hex | 2a90dd4bb87 |
2925104774023 has 2 divisors, whose sum is σ = 2925104774024. Its totient is φ = 2925104774022.
The previous prime is 2925104773993. The next prime is 2925104774159. The reversal of 2925104774023 is 3204774015292.
2925104774023 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2925104774023 - 25 = 2925104773991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2925104774923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1462552387011 + 1462552387012.
It is an arithmetic number, because the mean of its divisors is an integer number (1462552387012).
Almost surely, 22925104774023 is an apocalyptic number.
2925104774023 is a deficient number, since it is larger than the sum of its proper divisors (1).
2925104774023 is an equidigital number, since it uses as much as digits as its factorization.
2925104774023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 846720, while the sum is 46.
The spelling of 2925104774023 in words is "two trillion, nine hundred twenty-five billion, one hundred four million, seven hundred seventy-four thousand, twenty-three".
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