Base | Representation |
---|---|
bin | 1010111111000110… |
… | …1100111100111111 |
3 | 21121112010212002011 |
4 | 2233301230330333 |
5 | 22014423320413 |
6 | 1204344112051 |
7 | 133036305016 |
oct | 25761547477 |
9 | 7545125064 |
10 | 2949041983 |
11 | 1283725988 |
12 | 6a3765627 |
13 | 37cc82074 |
14 | 1dd93da7d |
15 | 123d7a33d |
hex | afc6cf3f |
2949041983 has 2 divisors, whose sum is σ = 2949041984. Its totient is φ = 2949041982.
The previous prime is 2949041951. The next prime is 2949041989. The reversal of 2949041983 is 3891409492.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2949041983 - 25 = 2949041951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2949041989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1474520991 + 1474520992.
It is an arithmetic number, because the mean of its divisors is an integer number (1474520992).
Almost surely, 22949041983 is an apocalyptic number.
2949041983 is a deficient number, since it is larger than the sum of its proper divisors (1).
2949041983 is an equidigital number, since it uses as much as digits as its factorization.
2949041983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 559872, while the sum is 49.
The square root of 2949041983 is about 54305.0824785305. The cubic root of 2949041983 is about 1434.0368731794.
The spelling of 2949041983 in words is "two billion, nine hundred forty-nine million, forty-one thousand, nine hundred eighty-three".
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