Search a number
-
+
29741113793 = 131227031403
BaseRepresentation
bin11011101100101101…
…010110000111000001
32211202201011010021002
4123230231112013001
5441402211120133
621355103141345
72102004203366
oct335455260701
984681133232
1029741113793
11116820a0a96
1259202a4855
132a5c860ab1
141621cd846d
15b9103bce8
hex6ecb561c1

29741113793 has 4 divisors (see below), whose sum is σ = 29968145328. Its totient is φ = 29514082260.

The previous prime is 29741113783. The next prime is 29741113799. The reversal of 29741113793 is 39731114792.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 29741113793 - 28 = 29741113537 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (29741113799) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113515571 + ... + 113515832.

It is an arithmetic number, because the mean of its divisors is an integer number (7492036332).

Almost surely, 229741113793 is an apocalyptic number.

It is an amenable number.

29741113793 is a deficient number, since it is larger than the sum of its proper divisors (227031535).

29741113793 is a wasteful number, since it uses less digits than its factorization.

29741113793 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 227031534.

The product of its digits is 285768, while the sum is 47.

Subtracting 29741113793 from its reverse (39731114792), we obtain a palindrome (9990000999).

The spelling of 29741113793 in words is "twenty-nine billion, seven hundred forty-one million, one hundred thirteen thousand, seven hundred ninety-three".

Divisors: 1 131 227031403 29741113793