Base | Representation |
---|---|
bin | 1000101010000111000… |
… | …00101111010010100111 |
3 | 1001102212021021001221102 |
4 | 10111003200233102213 |
5 | 14333222230233312 |
6 | 344355104310315 |
7 | 30330652112603 |
oct | 4250340572247 |
9 | 1042767231842 |
10 | 297485399207 |
11 | 105187830527 |
12 | 497a331239b |
13 | 2208bb89749 |
14 | 105811b0503 |
15 | 7b11a4bec2 |
hex | 454382f4a7 |
297485399207 has 2 divisors, whose sum is σ = 297485399208. Its totient is φ = 297485399206.
The previous prime is 297485399191. The next prime is 297485399219. The reversal of 297485399207 is 702993584792.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 297485399207 - 24 = 297485399191 is a prime.
It is a super-4 number, since 4×2974853992074 (a number of 47 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (297485399297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 148742699603 + 148742699604.
It is an arithmetic number, because the mean of its divisors is an integer number (148742699604).
Almost surely, 2297485399207 is an apocalyptic number.
297485399207 is a deficient number, since it is larger than the sum of its proper divisors (1).
297485399207 is an equidigital number, since it uses as much as digits as its factorization.
297485399207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68584320, while the sum is 65.
The spelling of 297485399207 in words is "two hundred ninety-seven billion, four hundred eighty-five million, three hundred ninety-nine thousand, two hundred seven".
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