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29967990505471 is a prime number
BaseRepresentation
bin1101101000001011101110…
…11011011011111111111111
310221002220121210011221211201
412310011313123123333333
512411443421032133341
6143423034344400331
76212054512232554
oct664056733337777
9127086553157751
1029967990505471
119604398416047
12343bbb74760a7
131394c7a957345
1475865c0d4a2b
1536e809a64331
hex1b41776dbfff

29967990505471 has 2 divisors, whose sum is σ = 29967990505472. Its totient is φ = 29967990505470.

The previous prime is 29967990505451. The next prime is 29967990505483. The reversal of 29967990505471 is 17450509976992.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 29967990505471 - 213 = 29967990497279 is a prime.

It is a super-3 number, since 3×299679905054713 (a number of 41 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 29967990505394 and 29967990505403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (29967990505421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14983995252735 + 14983995252736.

It is an arithmetic number, because the mean of its divisors is an integer number (14983995252736).

Almost surely, 229967990505471 is an apocalyptic number.

29967990505471 is a deficient number, since it is larger than the sum of its proper divisors (1).

29967990505471 is an equidigital number, since it uses as much as digits as its factorization.

29967990505471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 385786800, while the sum is 73.

The spelling of 29967990505471 in words is "twenty-nine trillion, nine hundred sixty-seven billion, nine hundred ninety million, five hundred five thousand, four hundred seventy-one".