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3000143000143 is a prime number
BaseRepresentation
bin101011101010000110011…
…101010011001001001111
3101121210220010100102202201
4223222012131103021033
5343123243102001033
610214125140302331
7426516224511112
oct53520635231117
911553803312681
103000143000143
11a57398567913
124055459a19a7
13189bb234a983
14a52c9cbc579
155309208e47d
hex2ba8675324f

3000143000143 has 2 divisors, whose sum is σ = 3000143000144. Its totient is φ = 3000143000142.

The previous prime is 3000143000093. The next prime is 3000143000159. The reversal of 3000143000143 is 3410003410003.

It is a strong prime.

It is an emirp because it is prime and its reverse (3410003410003) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3000143000143 - 233 = 2991553065551 is a prime.

3000143000143 is a modest number, since divided by 143000143 gives 3 as remainder.

It is a self number, because there is not a number n which added to its sum of digits gives 3000143000143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3000143000243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1500071500071 + 1500071500072.

It is an arithmetic number, because the mean of its divisors is an integer number (1500071500072).

Almost surely, 23000143000143 is an apocalyptic number.

3000143000143 is a deficient number, since it is larger than the sum of its proper divisors (1).

3000143000143 is an equidigital number, since it uses as much as digits as its factorization.

3000143000143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 3000143000143 its reverse (3410003410003), we get a palindrome (6410146410146).

The spelling of 3000143000143 in words is "three trillion, one hundred forty-three million, one hundred forty-three", and thus it is an aban number.