Base | Representation |
---|---|
bin | 1101101001001101001010… |
… | …10100111110100000100001 |
3 | 10221020021022001002112022001 |
4 | 12310212211110332200201 |
5 | 12413032342244131423 |
6 | 143451124310044001 |
7 | 6214440201462010 |
oct | 664464524764041 |
9 | 127207261075261 |
10 | 30003120302113 |
11 | 961828525a232 |
12 | 3446980349601 |
13 | 1398388a2506a |
14 | 75a23194aa77 |
15 | 3706b3bd2cad |
hex | 1b49a553e821 |
30003120302113 has 4 divisors (see below), whose sum is σ = 34289280345280. Its totient is φ = 25716960258948.
The previous prime is 30003120302081. The next prime is 30003120302149. The reversal of 30003120302113 is 31120302130003.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 30003120302113 - 25 = 30003120302081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (30003120302173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2143080021573 + ... + 2143080021586.
It is an arithmetic number, because the mean of its divisors is an integer number (8572320086320).
Almost surely, 230003120302113 is an apocalyptic number.
It is an amenable number.
30003120302113 is a deficient number, since it is larger than the sum of its proper divisors (4286160043167).
30003120302113 is an equidigital number, since it uses as much as digits as its factorization.
30003120302113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4286160043166.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 30003120302113 its reverse (31120302130003), we get a palindrome (61123422432116).
The spelling of 30003120302113 in words is "thirty trillion, three billion, one hundred twenty million, three hundred two thousand, one hundred thirteen".
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