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30004010341 = 191579158439
BaseRepresentation
bin11011111100011000…
…001101110101100101
32212110000211122112021
4123330120031311211
5442422011312331
621441134023141
72111345610544
oct337430156545
985400748467
1030004010341
11117a7533068
125994347ab1
132aa216a596
141648bb015b
15ba916c211
hex6fc60dd65

30004010341 has 4 divisors (see below), whose sum is σ = 31583168800. Its totient is φ = 28424851884.

The previous prime is 30004010299. The next prime is 30004010381. The reversal of 30004010341 is 14301040003.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14301040003 = 116312296681.

It is not a de Polignac number, because 30004010341 - 225 = 29970455909 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (30004010381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 789579201 + ... + 789579238.

It is an arithmetic number, because the mean of its divisors is an integer number (7895792200).

Almost surely, 230004010341 is an apocalyptic number.

It is an amenable number.

30004010341 is a deficient number, since it is larger than the sum of its proper divisors (1579158459).

30004010341 is a wasteful number, since it uses less digits than its factorization.

30004010341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1579158458.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 30004010341 its reverse (14301040003), we get a palindrome (44305050344).

The spelling of 30004010341 in words is "thirty billion, four million, ten thousand, three hundred forty-one".

Divisors: 1 19 1579158439 30004010341