Search a number
-
+
30005055553 = 112727732323
BaseRepresentation
bin11011111100011100…
…001101000001000001
32212110002210202021211
4123330130031001001
5442422243234203
621441212250121
72111360523034
oct337434150101
985402722254
1030005055553
11117a8087380
125994770941
132aa2445255
141648da301b
15ba92c6c6d
hex6fc70d041

30005055553 has 4 divisors (see below), whose sum is σ = 32732787888. Its totient is φ = 27277323220.

The previous prime is 30005055541. The next prime is 30005055601. The reversal of 30005055553 is 35555050003.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-30005055553 is a prime.

It is a super-2 number, since 2×300050555532 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (30005055503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1363866151 + ... + 1363866172.

It is an arithmetic number, because the mean of its divisors is an integer number (8183196972).

Almost surely, 230005055553 is an apocalyptic number.

It is an amenable number.

30005055553 is a deficient number, since it is larger than the sum of its proper divisors (2727732335).

30005055553 is a wasteful number, since it uses less digits than its factorization.

30005055553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2727732334.

The product of its (nonzero) digits is 28125, while the sum is 31.

The spelling of 30005055553 in words is "thirty billion, five million, fifty-five thousand, five hundred fifty-three".

Divisors: 1 11 2727732323 30005055553