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30005440153 = 138925933829
BaseRepresentation
bin11011111100011101…
…101010111010011001
32212110010112021212021
4123330131222322121
5442422343041103
621441224414441
72111364014233
oct337435527231
985403467767
1030005440153
11117a831a327
125994917421
132aa254b320
141649063253
15ba9350bbd
hex6fc76ae99

30005440153 has 8 divisors (see below), whose sum is σ = 32676625800. Its totient is φ = 27386122368.

The previous prime is 30005440139. The next prime is 30005440169. The reversal of 30005440153 is 35104450003.

It can be written as a sum of positive squares in 4 ways, for example, as 738100224 + 29267339929 = 27168^2 + 171077^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 30005440153 - 221 = 30003343001 is a prime.

It is not an unprimeable number, because it can be changed into a prime (30005449153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12965758 + ... + 12968071.

It is an arithmetic number, because the mean of its divisors is an integer number (4084578225).

Almost surely, 230005440153 is an apocalyptic number.

It is an amenable number.

30005440153 is a deficient number, since it is larger than the sum of its proper divisors (2671185647).

30005440153 is a wasteful number, since it uses less digits than its factorization.

30005440153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25933931.

The product of its (nonzero) digits is 3600, while the sum is 25.

Adding to 30005440153 its reverse (35104450003), we get a palindrome (65109890156).

The spelling of 30005440153 in words is "thirty billion, five million, four hundred forty thousand, one hundred fifty-three".

Divisors: 1 13 89 1157 25933829 337139777 2308110781 30005440153