Base | Representation |
---|---|
bin | 101011101010011111000… |
… | …000111101000011110111 |
3 | 101121211221211121012101201 |
4 | 223222133000331003313 |
5 | 343130114040000210 |
6 | 10214234055033331 |
7 | 426532356452044 |
oct | 53523700750367 |
9 | 11554854535351 |
10 | 3000555000055 |
11 | a5758a089508 |
12 | 40563b96b847 |
13 | 189c498011c2 |
14 | a53288c81cb |
15 | 530b832353a |
hex | 2ba9f03d0f7 |
3000555000055 has 48 divisors (see below), whose sum is σ = 3756744800640. Its totient is φ = 2300556347264.
The previous prime is 3000555000029. The next prime is 3000555000061. The reversal of 3000555000055 is 5500005550003.
It is not a de Polignac number, because 3000555000055 - 27 = 3000554999927 is a prime.
It is a super-2 number, since 2×30005550000552 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3000554999987 and 3000555000032.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 331219116 + ... + 331228174.
It is an arithmetic number, because the mean of its divisors is an integer number (78265516680).
Almost surely, 23000555000055 is an apocalyptic number.
3000555000055 is a deficient number, since it is larger than the sum of its proper divisors (756189800585).
3000555000055 is a wasteful number, since it uses less digits than its factorization.
3000555000055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9696 (or 9667 counting only the distinct ones).
The product of its (nonzero) digits is 9375, while the sum is 28.
The spelling of 3000555000055 in words is "three trillion, five hundred fifty-five million, fifty-five", and thus it is an aban number.
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