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300120153 = 3100040051
BaseRepresentation
bin10001111000110…
…111100001011001
3202220201200110020
4101320313201121
51103312321103
645440341053
710302656604
oct2170674131
9686650406
10300120153
11144456793
1284614789
134a2406b8
142bc0533b
151b534753
hex11e37859

300120153 has 4 divisors (see below), whose sum is σ = 400160208. Its totient is φ = 200080100.

The previous prime is 300120137. The next prime is 300120157. The reversal of 300120153 is 351021003.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 351021003 = 3117007001.

It is a cyclic number.

It is not a de Polignac number, because 300120153 - 24 = 300120137 is a prime.

It is not an unprimeable number, because it can be changed into a prime (300120157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50020023 + ... + 50020028.

It is an arithmetic number, because the mean of its divisors is an integer number (100040052).

Almost surely, 2300120153 is an apocalyptic number.

It is an amenable number.

300120153 is a deficient number, since it is larger than the sum of its proper divisors (100040055).

300120153 is a wasteful number, since it uses less digits than its factorization.

300120153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100040054.

The product of its (nonzero) digits is 90, while the sum is 15.

The square root of 300120153 is about 17323.9762468089. The cubic root of 300120153 is about 669.5223096837.

Adding to 300120153 its reverse (351021003), we get a palindrome (651141156).

The spelling of 300120153 in words is "three hundred million, one hundred twenty thousand, one hundred fifty-three".

Divisors: 1 3 100040051 300120153