Base | Representation |
---|---|
bin | 101011101101101100111… |
… | …100110010000111001011 |
3 | 101122011212121211001022222 |
4 | 223231230330302013023 |
5 | 343204203030410011 |
6 | 10220005000004255 |
7 | 430014111543341 |
oct | 53555474620713 |
9 | 11564777731288 |
10 | 3004010013131 |
11 | a58aa2379a16 |
12 | 406244a6068b |
13 | 18a37a54913a |
14 | a55756d5991 |
15 | 5321b7e5ddb |
hex | 2bb6cf321cb |
3004010013131 has 2 divisors, whose sum is σ = 3004010013132. Its totient is φ = 3004010013130.
The previous prime is 3004010013113. The next prime is 3004010013139. The reversal of 3004010013131 is 1313100104003.
Together with previous prime (3004010013113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3004010013131 is a prime.
It is a super-2 number, since 2×30040100131312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3004010013139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1502005006565 + 1502005006566.
It is an arithmetic number, because the mean of its divisors is an integer number (1502005006566).
Almost surely, 23004010013131 is an apocalyptic number.
3004010013131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3004010013131 is an equidigital number, since it uses as much as digits as its factorization.
3004010013131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 3004010013131 its reverse (1313100104003), we get a palindrome (4317110117134).
The spelling of 3004010013131 in words is "three trillion, four billion, ten million, thirteen thousand, one hundred thirty-one".
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