Base | Representation |
---|---|
bin | 1011001100001111… |
… | …0001110010001011 |
3 | 21202100202200221211 |
4 | 2303003301302023 |
5 | 22123023041021 |
6 | 1214032313551 |
7 | 134305350025 |
oct | 26303616213 |
9 | 7670680854 |
10 | 3004112011 |
11 | 13018198aa |
12 | 6ba0a28b7 |
13 | 38b4c4094 |
14 | 206d97015 |
15 | 128b073e1 |
hex | b30f1c8b |
3004112011 has 4 divisors (see below), whose sum is σ = 3004849000. Its totient is φ = 3003375024.
The previous prime is 3004111969. The next prime is 3004112047. The reversal of 3004112011 is 1102114003.
3004112011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1102114003 = 313 ⋅3521131.
It is a cyclic number.
It is not a de Polignac number, because 3004112011 - 29 = 3004111499 is a prime.
It is a super-3 number, since 3×30041120113 (a number of 29 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3004111982 and 3004112000.
It is not an unprimeable number, because it can be changed into a prime (3004112411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 362346 + ... + 370543.
It is an arithmetic number, because the mean of its divisors is an integer number (751212250).
Almost surely, 23004112011 is an apocalyptic number.
3004112011 is a deficient number, since it is larger than the sum of its proper divisors (736989).
3004112011 is an equidigital number, since it uses as much as digits as its factorization.
3004112011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 736988.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 3004112011 is about 54809.7802495139. The cubic root of 3004112011 is about 1442.9082190353.
Adding to 3004112011 its reverse (1102114003), we get a palindrome (4106226014).
The spelling of 3004112011 in words is "three billion, four million, one hundred twelve thousand, eleven".
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