Base | Representation |
---|---|
bin | 101011110011010011010… |
… | …010101100011000000011 |
3 | 101122202101121102122002011 |
4 | 223303103102230120003 |
5 | 343304011113001011 |
6 | 10222441321433351 |
7 | 430316102565256 |
oct | 53632322543003 |
9 | 11582347378064 |
10 | 3010022000131 |
11 | a605a7a47813 |
12 | 40744233b857 |
13 | 18aac7c50cb3 |
14 | a5985d4509d |
15 | 5346e4ea621 |
hex | 2bcd34ac603 |
3010022000131 has 4 divisors (see below), whose sum is σ = 3066814868112. Its totient is φ = 2953229132152.
The previous prime is 3010022000119. The next prime is 3010022000159. The reversal of 3010022000131 is 1310002200103.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3010022000131 - 25 = 3010022000099 is a prime.
It is a super-2 number, since 2×30100220001312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3010022000171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28396433911 + ... + 28396434016.
It is an arithmetic number, because the mean of its divisors is an integer number (766703717028).
Almost surely, 23010022000131 is an apocalyptic number.
3010022000131 is a deficient number, since it is larger than the sum of its proper divisors (56792867981).
3010022000131 is an equidigital number, since it uses as much as digits as its factorization.
3010022000131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56792867980.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 3010022000131 its reverse (1310002200103), we get a palindrome (4320024200234).
The spelling of 3010022000131 in words is "three trillion, ten billion, twenty-two million, one hundred thirty-one", and thus it is an aban number.
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