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30105215313 = 310035071771
BaseRepresentation
bin11100000010011010…
…010010000101010001
32212201002021101122120
4130002122102011101
5443123413342223
621455151124453
72114015052015
oct340232220521
985632241576
1030105215313
1111849677938
125a02213729
132aba113694
1416583d6545
15bb2eadbe3
hex702692151

30105215313 has 4 divisors (see below), whose sum is σ = 40140287088. Its totient is φ = 20070143540.

The previous prime is 30105215303. The next prime is 30105215321. The reversal of 30105215313 is 31351250103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 30105215313 - 24 = 30105215297 is a prime.

It is not an unprimeable number, because it can be changed into a prime (30105215303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5017535883 + ... + 5017535888.

It is an arithmetic number, because the mean of its divisors is an integer number (10035071772).

Almost surely, 230105215313 is an apocalyptic number.

It is an amenable number.

30105215313 is a deficient number, since it is larger than the sum of its proper divisors (10035071775).

30105215313 is a wasteful number, since it uses less digits than its factorization.

30105215313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10035071774.

The product of its (nonzero) digits is 1350, while the sum is 24.

Adding to 30105215313 its reverse (31351250103), we get a palindrome (61456465416).

The spelling of 30105215313 in words is "thirty billion, one hundred five million, two hundred fifteen thousand, three hundred thirteen".

Divisors: 1 3 10035071771 30105215313